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My question 7 you are given a ferris wheel rotating at two revolutions minutes and the hbu have a center oh and the diameter of 16 meters so the radius is 8 meters a person's on the view is that the precision as so that SP is X and anger as o P is Theta pate you just use cosines rule to show that x square is equal to 12 8-1 2a cosine theta okay now let's look at this triangle then okay a prank or signs rule we have x square is equal to a square plus x square minus 2 times a and a cosine theta right this is wrong to be negative so we get what is required right hobby as show then DX DT is equal to 64 sine theta over X the t30 T to do that with differentiates expressions that we obtained here square so but the tragedies we have 2x DX DT differentiate 128 is 0 different' here we have negative signs so and then d theta/dt so obtain the value 128 sine theta d theta dt right then we arranged the whole expressions we obtain what is required be now we move on to Patsy you have to find d theta/dt d theta/dt is actually the rate of change of the anger right so let's look at this rotating so rate of change of this angle theta and we are given also in your first pop the question that's a change of anger is two revolutions per minute right and to revolution one revolution is one sucker and these two tiny hands we have to tie x 24 point per minute can we move on to the last part of these questions you also find the rate at least SP is changing SP right the length of x is changing so you actually also find the rate of change of X DX DT and from paddy we have obtained this results and we also from here that we know d theta DT is equal to 4 pi so we just put 4 pi into the expressions and we also known from Pat a that s is 8 meters above p all right so using the question let me have obtained from a we substitute the value of theta go to 19 to the expression and hands we get the value of x when x is equal to 28 meters is equal to square root of 128 so we put x equal to square one to a into the expressions entity deputies go to for time and we obtain the results for the last part of these questions.